Flexible input-file naming possible now.
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305122d02b
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e2ec6b3574
@ -477,7 +477,7 @@ def runProgram(cmd, parameter=None):
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subprocess.check_output('{} | tee /dev/stderr'.format(cmd), shell=True)
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def which(program):
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def which(program, infile=None):
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"""
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takes a program name and returns the full path to the executable or None
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modified after: http://stackoverflow.com/questions/377017/test-if-executable-exists-in-python
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@ -490,7 +490,12 @@ def which(program):
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for key in settings.allKeys():
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if 'binPath' in key:
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os.environ['PATH'] += ':{0}'.format(settings.value(key))
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bpath = os.path.join(os.path.expanduser('~'), '.pylot', 'autoPyLoT.in')
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if infile is None:
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# use default parameter-file name
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bpath = os.path.join(os.path.expanduser('~'), '.pylot', 'pylot.in')
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else:
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bpath = os.path.join(os.path.expanduser('~'), '.pylot', infile)
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if os.path.exists(bpath):
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nllocpath = ":" + AutoPickParameter(bpath).get('nllocbin')
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os.environ['PATH'] += nllocpath
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